Calculate the mass of sugar, C12H22O11, in 280.4 mL of a 1.49 M solution of sugar.

(atomic weights: C = 12.01, H = 1.008, O = 16.00)

M=mass/molmass*volume

mass= M*molmass*volume
= 1.49*(12.01*12+1.008*22+11*16.00)*.2804

To calculate the mass of sugar in the solution, we need to follow these steps:

Step 1: Determine the moles of C12H22O11 in the solution.
To calculate the moles of C12H22O11, we can use the formula: Moles = Molarity x Volume
Given:
Molarity (M) = 1.49 M
Volume (V) = 280.4 mL = 0.2804 L

Moles of C12H22O11 = Molarity x Volume
= 1.49 M x 0.2804 L
= 0.4179 moles

Step 2: Calculate the molar mass of C12H22O11.
The molar mass of C12H22O11 can be calculated by adding up the atomic masses of carbon (C), hydrogen (H), and oxygen (O) in C12H22O11.

Molar mass of C12H22O11 = (12.01 g/mol x 12) + (1.008 g/mol x 22) + (16.00 g/mol x 11)
= 144.12 g/mol + 22.176 g/mol + 176.00 g/mol
= 342.296 g/mol

Step 3: Calculate the mass of C12H22O11 in the solution.
Mass of C12H22O11 = Moles of C12H22O11 x Molar mass of C12H22O11
= 0.4179 moles x 342.296 g/mol
= 142.91 grams

Therefore, the mass of C12H22O11 in 280.4 mL of a 1.49 M solution of sugar is 142.91 grams.