A person walks 10.4 degrees north of east for 4.19km. Another person walks due north, then due east to arrive at the same location. How far due north would this person walk? Answer in units of km.
lol - the other half of the problem
4.19 sin 10.4
4.19 km
find the y component after you set up the triangle.
To solve this problem, we can break it down into two parts:
Part 1: Person 1 walks 10.4 degrees north of east for 4.19 km.
Since they walk in a north of east direction, we can use trigonometry to find the components of their displacement.
The northward component is given by 4.19 km * sin(10.4 degrees).
The eastward component is given by 4.19 km * cos(10.4 degrees).
Part 2: Person 2 walks due north, then due east to arrive at the same location.
Since Person 2 walks due north and due east, their displacement will have only a northward component and an eastward component. Let's say the distance they walk due north is x km.
Now, since both persons arrive at the same location, the northward component of Person 1's displacement should be equal to the northward component of Person 2's displacement, and the eastward component should be equal as well.
We already know the eastward component of Person 1's displacement, which is 4.19 km * cos(10.4 degrees). Since Person 2 walks due east, it means their eastward component is 0 km.
Now, let's set up the equation for the northward components:
4.19 km * sin(10.4 degrees) = x km
To find the value of x, we can solve this equation:
x = (4.19 km * sin(10.4 degrees)) / 1
Using a calculator, we find that x ≈ 0.726 km.
Therefore, the person walking due north would need to walk approximately 0.726 km in order to arrive at the same location.