A lifeguard swims with her head just above the water. What is the volume of the submerged part of her body if she weighs 600 N?
Would I need to divide by 9800 or 62.4?
600/9800
To determine the volume of the submerged part of the lifeguard's body, you would need to divide her weight by the density of water.
The density of water is approximately 1000 kg/m^3 or 1000 N/m^3.
Since weight is a force measured in Newtons (N), to convert her weight from Newtons to kilograms, you would need to divide by the acceleration due to gravity, which is approximately 9.8 m/s^2. Dividing by 9.8 gives you her mass in kilograms (kg).
So, to calculate the volume, you would divide her weight (600 N) by the density of water (1000 N/m^3).
Volume = Weight / Density
Volume = 600 N / 1000 N/m^3
Therefore, you would divide by 1000 N/m^3, so the answer is 0.6 cubic meters.
To find the volume of the submerged part of her body, you need to determine the buoyant force acting on her. The buoyant force is equal to the weight of the liquid displaced by the submerged part of her body.
To calculate the buoyant force, you can use Archimedes' principle, which states that the buoyant force is equal to the weight of the fluid displaced.
First, let's determine the weight of the fluid displaced. The weight of the fluid displaced is equal to the weight of the lifeguard, which is 600 N.
Now, let's calculate the buoyant force using the weight of the fluid displaced. The buoyant force is also equal to the weight of the submerged part of her body.
So, the volume of the submerged part of her body is the weight of the fluid displaced (600 N) divided by the density of the fluid.
To calculate the volume, you need to know the density of the liquid. If the problem doesn't provide this information, you can assume that the liquid is water. The density of water is approximately 1000 kg/m³.
Now, the equation to calculate volume is:
Volume = Weight of fluid displaced / Density of the fluid
Substituting the values, we have:
Volume = 600 N / (1000 kg/m³)
Make sure to convert the weight from newtons to kg by dividing it by the acceleration due to gravity (9.8 m/s²), as weight = mass x gravity.
Volume = (600 N / 9.8 m/s²) / (1000 kg/m³)
Simplifying further, we have:
Volume = 61.22 m³
So, the volume of the submerged part of the lifeguard's body is approximately 61.22 cubic meters.
To answer your question, you only need to divide by 1000 kg/m³, which is the density of water. Dividing by 9800 or 62.4 is not necessary for this specific problem.