Complete and balance the following reactions, where applicable. If no reaction occurs, write N.R.
Li + H2O ---->
KCI + F2 --->
Au + HNO3 --->
CI2 + NaF ---->
Li + Fe(NO3)3 --->
What trouble are you having doing this? All look like single replacement reactions. Cl2 + NaF is NR.
Au will not react with HNO3 either.
I don't understand
Sure! Let's balance each of the reactions one by one:
1) Li + H2O ---->
To balance this equation, we need to ensure that the number of atoms on both sides of the equation is equal.
First, let's balance lithium (Li). There is one Li atom on the left side, so we need to have one Li atom on the right side as well.
Now, let's balance the hydrogen (H) atoms. There are two hydrogen atoms in water (H2O) on the right side, so we need to have two hydrogen atoms on the left side as well. We can achieve this by adding a coefficient of 2 in front of Li:
2Li + H2O ---->
Finally, let's balance the oxygen (O) atoms. There are two oxygen atoms in water (H2O) on the right side, so we need two oxygen atoms on the left side as well. We can achieve this by adding a coefficient of 2 in front of H2O:
2Li + 2H2O ---->
Therefore, the balanced equation is 2Li + 2H2O ---->
2) KCl + F2 ---->
To balance this equation, we need to ensure that the number of atoms on both sides of the equation is equal.
Let's first balance the potassium (K) atoms. There is one K atom on the left side, so we need to have one K atom on the right side as well.
Now, let's balance the chlorine (Cl) atoms. There is one Cl atom on the left side, so we need to have one Cl atom on the right side as well.
Next, let's balance the fluorine (F) atoms. There are two F atoms in F2 on the right side, so we need to have two F atoms on the left side as well. We can achieve this by adding a coefficient of 2 in front of KCl:
2KCl + F2 ---->
Therefore, the balanced equation is 2KCl + F2 ---->
3) Au + HNO3 ---->
To balance this equation, we need to ensure that the number of atoms on both sides of the equation is equal.
Let's first balance the gold (Au) atoms. There is one Au atom on the left side, so we need to have one Au atom on the right side as well.
Now, let's balance the nitrogen (N) atoms. There is one N atom in HNO3 on the right side, so we need to have one N atom on the left side as well.
Next, let's balance the hydrogen (H) atoms. There is one H atom in HNO3 on the right side, so we need to have one H atom on the left side as well.
Finally, let's balance the oxygen (O) atoms. There three O atoms in HNO3 on the right side, so we need to have three O atoms on the left side. We can achieve this by adding a coefficient of 3 in front of HNO3:
Au + 3HNO3 ---->
Therefore, the balanced equation is Au + 3HNO3 ---->
4) Cl2 + NaF ---->
To balance this equation, we need to ensure that the number of atoms on both sides of the equation is equal.
Let's first balance the chlorine (Cl) atoms. There are two Cl atoms in Cl2 on the left side, so we need to have two Cl atoms on the right side as well. We can achieve this by adding a coefficient of 2 in front of NaF:
Cl2 + 2NaF ---->
Finally, let's balance the sodium (Na) atoms. There are two Na atoms in 2NaF on the right side, so we need to have two Na atoms on the left side as well. We can achieve this by adding a coefficient of 2 in front of NaF:
Cl2 + 2NaF ---->
Therefore, the balanced equation is Cl2 + 2NaF ---->
5) Li + Fe(NO3)3 ---->
To balance this equation, we need to ensure that the number of atoms on both sides of the equation is equal.
Let's first balance the lithium (Li) atoms. There is one Li atom on the left side, so we need to have one Li atom on the right side as well.
Now, let's balance the iron (Fe) atoms. There is one Fe atom in Fe(NO3)3 on the right side, so we need to have one Fe atom on the left side as well.
Next, let's balance the nitrogen (N) atoms. There three N atoms in Fe(NO3)3 on the right side, so we need to have three N atoms on the left side. We can achieve this by adding a coefficient of 3 in front of Li:
3Li + Fe(NO3)3 ---->
Finally, let's balance the oxygen (O) atoms. There nine O atoms in Fe(NO3)3 on the right side, so we need to have nine O atoms on the left side. We can achieve this by adding a coefficient of 3 in front of Li:
3Li + Fe(NO3)3 ---->
Therefore, the balanced equation is 3Li + Fe(NO3)3 ---->