During burnouts at the local drag strip, a dragster’s 45.0kg tire rotates at a speed of 35.0m/s. If the tire has a radius of 0.500m what is the centripetal force acting on the center of the tire rim during this burnout?

To find the centripetal force acting on the center of the tire rim, you can use the formula:

Centripetal force (F) = mass (m) × velocity (v)² / radius (r)

Given:
mass (m) = 45.0 kg
velocity (v) = 35.0 m/s
radius (r) = 0.500 m

Plugging in these values into the formula, we can calculate the centripetal force:

F = (45.0 kg) × (35.0 m/s)² / 0.500 m

First, square the velocity:

F = (45.0 kg) × (1225.0 m²/s²) / 0.500 m

Next, divide the product of mass and velocity squared by the radius:

F = (45.0 kg) × (1225.0 m²/s²) / 0.500 m

Now, we can simplify the equation:

F = 55012.5 kg·m/s²

Therefore, the centripetal force acting on the center of the tire rim during the burnout is 55012.5 kg·m/s².