Hi the question asks me to calculate the mass of calcium carbonate that must be decomposed to produce 14kg of calcium oxide.
I think I've gone wrong somewhere, do you write 14000g or 14kg etc, could you help?
I did: Moles CaO=(Mass CaO/Mr CaO)
=1400/56
=25
CaO:CaCO3
1:1
25:25
Mass CaCo= Moles CaCO x Mr CaCO
=25 x 68
=1700
=1.7kg
CaCO3 ==> CaO + CO2
The process looks ok at first glance but the numbers are wrong. You should have used 14 kg = 14,000 g
Then 14,000/56 = 250
250 mols CaO (I would have used 56.1 for molar mass CaO)
Then 25o mols CaO = 250 mols CaCO3
Then mass CaCO3 = mols CaCO3 x molar mass CaCO3 = 250 x 100.(not 68)
The answer will be in units of grams. Convert to kg if that is needed.
Thank you so much!
To answer this question correctly, you need to keep track of the units you are using for mass. In this case, it is important to be consistent with either grams (g) or kilograms (kg).
Since the given mass is 14 kg of calcium oxide (CaO), let's convert it to grams:
14 kg = 14,000 g
Now we need to find the mass of calcium carbonate (CaCO3) that needs to be decomposed to produce 14 kg (or 14,000 g) of calcium oxide.
To do this, we can use stoichiometry and the molar mass relationship between calcium carbonate and calcium oxide.
The balanced chemical equation for the decomposition of calcium carbonate is:
CaCO3 -> CaO + CO2
According to the balanced equation, 1 mole of calcium carbonate produces 1 mole of calcium oxide.
1 mole of any substance is equal to its molar mass in grams. The molar mass of calcium carbonate (CaCO3) is approximately 100 g/mol, and the molar mass of calcium oxide (CaO) is approximately 56 g/mol.
Now let's calculate the mass of calcium carbonate using the given mass of calcium oxide:
Moles of CaO = (Mass of CaO / Molar mass of CaO)
= 14,000 g / 56 g/mol
= 250 mol
Since the stoichiometry between calcium oxide and calcium carbonate is 1:1, the moles of calcium carbonate needed will be the same as the moles of calcium oxide:
Moles of CaCO3 = 250 mol
To find the mass of calcium carbonate, multiply the moles by its molar mass:
Mass of CaCO3 = Moles of CaCO3 x Molar mass of CaCO3
= 250 mol x 100 g/mol
= 25,000 g
Now, if you want to convert this mass from grams to kilograms, you can divide it by 1000:
Mass of CaCO3 = 25,000 g / 1000
= 25 kg
Therefore, the mass of calcium carbonate that must be decomposed to produce 14 kg of calcium oxide is 25 kg.