Suppose 55.3 L of a gas is at a temperature of -73. °C.
If its temperature is increased to 411. °C, what will its volume be then?
(V1/T1) = (V2/T2)
T must be in kelvin
The Temp should increase
To solve this problem, we can use the combined gas law formula:
(P1 × V1) / (T1) = (P2 × V2) / (T2)
Where:
P1 = initial pressure (which is not given in the problem)
V1 = initial volume (given as 55.3 L)
T1 = initial temperature in Kelvin (we need to convert -73. °C to Kelvin)
P2 = final pressure (which is not given in the problem)
V2 = final volume (what we're trying to find)
T2 = final temperature in Kelvin (we need to convert 411. °C to Kelvin)
First, let's convert the initial temperature (-73. °C) and final temperature (411. °C) to Kelvin:
T1 = -73 °C + 273.15 = 200.15 K
T2 = 411 °C + 273.15 = 684.15 K
Now, we can rewrite the combined gas law equation using the given values and the variables we're solving for:
(P1 × 55.3) / (200.15) = (P2 × V2) / (684.15)
As we don't have information about the pressures (P1 and P2), we can assume that they remain constant. This means that the pressure cancels out from the equation, and we can simplify the equation to solve for V2:
55.3 / 200.15 = V2 / 684.15
Now, we can solve for V2:
V2 = (55.3 / 200.15) × 684.15
Calculating this expression:
V2 ≈ 150.22 L
Therefore, when the gas is heated to 411. °C, the volume will be approximately 150.22 L.
To solve this problem, we can use the combined gas law, which states that:
(P1 * V1) / (T1) = (P2 * V2) / (T2),
where P1 and P2 are the initial and final pressures, V1 and V2 are the initial and final volumes, and T1 and T2 are the initial and final temperatures.
Given:
- Initial volume (V1) is 55.3 L,
- Initial temperature (T1) is -73 °C,
- Final temperature (T2) is 411 °C.
We need to find the final volume (V2).
First, we need to convert the temperatures from Celsius to Kelvin, as Kelvin is the absolute temperature scale. The conversion formula is:
T(K) = T(°C) + 273.15.
Converting the initial and final temperatures:
T1 = -73 + 273.15 = 200.15 K,
T2 = 411 + 273.15 = 684.15 K.
Now, let's use the combined gas law equation:
(P1 * V1) / T1 = (P2 * V2) / T2.
Assuming the pressure remains constant, we can cancel it out:
V1 / T1 = V2 / T2.
Rearranging the equation to solve for V2:
V2 = (V1 * T2) / T1.
Plugging in the given values:
V2 = (55.3 * 684.15) / 200.15.
Calculating this expression will give you the final volume (V2) in liters.