How many moles of Ca(OH)2 are in 4.10 kg of
Ca(OH)2?
Answer in units of mol
mols = grams/molar mass = ?
Remember to convert kg to g first.
To find the number of moles of Ca(OH)2, you need to use its molar mass. The molar mass of Ca(OH)2 is the sum of the atomic masses of calcium (Ca), oxygen (O), and hydrogen (H) atoms.
The atomic mass of calcium (Ca) is 40.08 g/mol, the atomic mass of oxygen (O) is 16.00 g/mol, and the atomic mass of hydrogen (H) is 1.01 g/mol.
Calculating the molar mass of Ca(OH)2:
Ca: 1 atom x 40.08 g/mol = 40.08 g/mol
O: 2 atoms x 16.00 g/mol = 32.00 g/mol
H: 2 atoms x 1.01 g/mol = 2.02 g/mol
Adding up the masses:
40.08 g/mol + 32.00 g/mol + 2.02 g/mol = 74.10 g/mol
Now, you can use this molar mass to find the number of moles. The given mass is 4.10 kg, but you need to convert it to grams.
Converting kg to grams:
1 kg = 1000 g, so 4.10 kg = 4.10 x 1000 = 4100 g
Now, use the molar mass to calculate the moles of Ca(OH)2:
Moles = Mass / Molar Mass
Moles = 4100 g / 74.10 g/mol
Calculating the moles:
Moles = 55.37 mol
Therefore, there are approximately 55.37 moles of Ca(OH)2 in 4.10 kg of Ca(OH)2.