A sample of neon gas at 1.20 atm compresses from 0.250 L to 0.125 L. If the temperature is held constant, what is the final pressure?

P1V1 = P2V2

To find the final pressure of the neon gas when it compresses from 0.250 L to 0.125 L, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when the temperature is constant.

Boyle's Law can be represented by the formula:

P1 * V1 = P2 * V2,

where P1 and V1 are the initial pressure and volume respectively, and P2 and V2 are the final pressure and volume.

Let's use this formula to solve the problem.

Given:
Initial pressure (P1) = 1.20 atm
Initial volume (V1) = 0.250 L
Final volume (V2) = 0.125 L
Unknown: Final pressure (P2)

We can plug in the values into the formula:

1.20 atm * 0.250 L = P2 * 0.125 L

Now, let's solve for P2:

(1.20 atm * 0.250 L) / 0.125 L = P2

P2 = 2.40 atm

Therefore, the final pressure of the neon gas, when it compresses from 0.250 L to 0.125 L at constant temperature, is 2.40 atm.