Trigonometry

Prove:
1-tanx/1+tanx=1-sin2x/cos2x

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  1. multiply by 1-tanx to get

    (1-tanx)^2/(1-tan^2 x)
    = (1-2tanx+tan^2 x)/(1-tan^2 x)
    = (1+tan^2 x)/(1-tan^2 x) - 2tanx/(1-tan^2 x)
    = sec^2x/(1-tan^2 x) - tan2x
    = 1/(cos^2x-sin^2x) - tan2x
    = 1/cos2x - sin2x/cos2x
    = (1-sin2x)/cos2x

    Your carelessness with parentheses threw me off for a while. I was reading the RS as 1-(sin2x/cos2x) using the normal order of operations.

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  2. lol im sorry. Thanks Steve! :)

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