Calculate the theoretical percentage of water present in cobalt (II) chloride hexahydrate, given that the molar mass is 237.93 g/mol and the molar mass of water in the compound is 108.12 g/mol.
Question 8 options:
220%
50.5%
6%
45.4%
45.4%
mass % H2O = (mass H2O/molar mass compound)*100 = ?
%H2O = (108.12/237.93)*100 = ?
Well, let's look at this equation rationally. According to the formula of cobalt (II) chloride hexahydrate, CoCl2 * 6H2O, we know that the molar mass of water is 108.12 g/mol. Now, if we multiply this mass by the six molecules of water, we get a total mass of 648.72 g/mol.
To find the percentage of water, we divide the molar mass of water (648.72 g/mol) by the molar mass of cobalt (II) chloride hexahydrate (237.93 g/mol) and then multiply by 100.
So, (648.72 g/mol / 237.93 g/mol) * 100 = 272.459...
Hmmm... 272.459% seems a bit nonsensical, don't you think? It's more than 100%! That's like trying to fit a clown car into a regular-sized parking space. Unfortunately, something went wrong in our calculations.
I suppose the true theoretical percentage of water in cobalt (II) chloride hexahydrate is closer to 45.4%, which is not as exciting as the idea of cramming water into a compound at over 200%. So, it looks like we've got a serious case of misplaced hydration humor. Better luck next time!
To calculate the theoretical percentage of water in cobalt (II) chloride hexahydrate, we first need to determine the ratio of water molecules to the total molar mass of the compound.
Cobalt (II) chloride hexahydrate is composed of a cobalt (II) ion (Co2+), two chloride ions (Cl-), and six water molecules (H2O). The molar mass of the compound is given as 237.93 g/mol.
Next, we need to determine the molar mass of the water in the compound, which is given as 108.12 g/mol.
To calculate the percentage of water in the compound, we need to consider the mass of water relative to the total mass of the compound.
The molar mass of water in the compound can be calculated as follows:
Molar mass of water = Molar mass of water molecules x Number of water molecules
= 108.12 g/mol x 6
= 648.72 g
The percentage of water in the cobalt (II) chloride hexahydrate is then calculated as follows:
Percentage of water = (Molar mass of water / Molar mass of compound) x 100%
= (648.72 g / 237.93 g/mol) x 100%
≈ 272.6 %
Since the percentage of water cannot be greater than 100%, we can conclude that the correct answer is not among the given answer options.