The solubility of sodium chloride (NaCl) was determined experimentally to be 35.7 g/ 100 g of water (H2O) at 200 C. How many grams of NaCl would dissolve in 50g of H2O at 200 C?
35.7 g x 50/100 = ?
17.85g of NaCl
To determine the number of grams of NaCl that would dissolve in 50g of H2O at 200°C, we can use a proportion based on the given solubility data.
The solubility of NaCl is given as 35.7 g/100 g of H2O at 200°C. This means that 100 g of water can dissolve 35.7 g of NaCl.
To find out how many grams of NaCl would dissolve in 50 g of water, we can set up a proportion:
(35.7 g NaCl) / (100 g H2O) = (x g NaCl) / (50 g H2O)
Now, we can cross-multiply and solve for 'x':
(35.7 g NaCl) * (50 g H2O) = (100 g H2O) * (x g NaCl)
1785 g NaCl = 100 g H2O * x
To isolate 'x', we divide both sides of the equation by 100 g H2O:
(1785 g NaCl) / (100 g H2O) = x
x = 17.85 g NaCl
Therefore, 17.85 grams of NaCl would dissolve in 50 grams of H2O at 200°C.