How do I do the following?

Write the net ionic equation for the following molecular equation.
3 CoCl2(aq) + 2 Na3PO4(aq) Co3(PO4)2(s) + 6 NaCl(aq)

To write the net ionic equation for the given molecular equation, you need to first write the ionic equation and then cancel out the spectator ions.

Here's how you can do it step by step:

Step 1: Write the balanced molecular equation:
3 CoCl2(aq) + 2 Na3PO4(aq) → Co3(PO4)2(s) + 6 NaCl(aq)

Step 2: Write the dissociated ionic equation by breaking down all the soluble compounds into their respective ions:
CoCl2(aq) --> Co2+(aq) + 2 Cl-(aq)
Na3PO4(aq) --> 3 Na+(aq) + PO4^3-(aq)
Co3(PO4)2(s) (s) - no dissociation, as it is a precipitate
NaCl(aq) --> Na+(aq) + Cl-(aq)

Step 3: Write the balanced net ionic equation by canceling out the spectator ions. These are ions that appear on both sides of the equation and do not participate in the reaction.
In this case, the spectator ions are the Na+ and Cl- ions since they appear on both sides of the equation.

Net ionic equation:
Co2+(aq) + 3 Cl-(aq) + 2 PO4^3-(aq) → Co3(PO4)2(s)

So, the net ionic equation for the given molecular equation is:
Co2+(aq) + 3 Cl-(aq) + 2 PO4^3-(aq) → Co3(PO4)2(s)