When you have 50ml of a 0.25M solution of KI in water. What should the final volume be is you want to reduce the concentration to .10M
mL1 x M1 = mL2 x M2
50 mL x 0.25M = mL2 x 0.1.
To calculate the final volume required to reduce the concentration of a solution, you can use the formula:
C1 × V1 = C2 × V2
Where:
C1 = initial concentration of the solution
V1 = initial volume of the solution
C2 = final concentration desired
V2 = final volume required
Let's plug in the values from your question:
C1 = 0.25M
V1 = 50ml
C2 = 0.10M
V2 = ?
Using the formula, we can rearrange it to solve for V2:
V2 = (C1 × V1) / C2
Substituting the given values:
V2 = (0.25M × 50ml) / 0.10M
Now, let's simplify the equation:
V2 = (12.5 mol/L × 50ml) / 0.10 mol/L
The units of moles per liter (mol/L) cancel out, leaving us with the unit of volume (ml):
V2 = (12.5 × 50) / 0.10 ml
V2 = 6250 / 0.10 ml
V2 = 62500 ml
Therefore, the final volume required to reduce the concentration of the solution to 0.10M would be 62500 ml.