Calculate the volume of concentrated NaOH solution (which contains 500.00g of NaOH per liter of solution) that you will need to make 1.00L of a 0.100M NaOH solution

Well, to calculate the volume of concentrated NaOH solution you need, we'll have to do some calculations. But before that, let's have a quick joke!

Why don't skeletons fight each other?

Because they don't have the guts!

Alright, now let's get back to business. To find the volume, we need to use the formula:

Volume (concentrated solution) x Concentration (concentrated solution) = Volume (final solution) x Concentration (final solution)

In this case, we know that the volume of the final solution is 1.00L and the concentration of the final NaOH solution is 0.100M.

Now let's solve it together.

Volume (concentrated solution) x (500.00g/L) = (1.00L) x (0.100M)

Now, to calculate the volume of the concentrated solution, we rearrange the equation:

Volume (concentrated solution) = (1.00L) x (0.100M) / (500.00g/L)

And when we calculate that expression, we find:

Volume (concentrated solution) = 0.002L = 2 milliliters

So, you will need approximately 2 milliliters of the concentrated NaOH solution.

I hope that helps, and don't hesitate to ask if you have any more questions!

To calculate the volume of concentrated NaOH solution needed to make 1.00L of a 0.100M NaOH solution, you can use the formula:

Concentration1 × Volume1 = Concentration2 × Volume2

Where:
Concentration1 is the concentration of the concentrated NaOH solution
Volume1 is the volume of the concentrated NaOH solution needed
Concentration2 is the desired concentration of the NaOH solution
Volume2 is the final volume of the NaOH solution

Given:
Concentration1 = 500.00 g/L
Volume1 = ?
Concentration2 = 0.100 M
Volume2 = 1.00 L

Let's solve for Volume1:

Concentration1 × Volume1 = Concentration2 × Volume2

500.00 g/L × Volume1 = 0.100 M × 1.00 L

Volume1 = (0.100 M × 1.00 L) / (500.00 g/L)

Volume1 = 0.0002 L = 0.2 mL

Therefore, you would need to measure 0.2 mL of the concentrated NaOH solution to make 1.00L of a 0.100M NaOH solution.

To calculate the volume of concentrated NaOH solution needed to make 1.00L of a 0.100M NaOH solution, we can use the equation:

M1V1 = M2V2

Where:
M1 = initial molar concentration of the NaOH solution (concentrated NaOH solution)
V1 = volume of the concentrated NaOH solution needed
M2 = final desired molar concentration of the NaOH solution (0.100M)
V2 = final desired volume of the NaOH solution (1.00L)

Rearranging the equation, we get:

V1 = (M2 * V2) / M1

Now let's plug in the given values:

M1 = 500.00 g/L (concentrated NaOH solution)
M2 = 0.100 mol/L (final desired molar concentration)
V2 = 1.00 L (final desired volume)

First, we need to convert M1 from grams per liter to moles per liter. To do this, we divide the given mass by the molar mass of NaOH, which is approximately 40.00 g/mol:

M1 = 500.00 g/L / 40.00 g/mol = 12.50 mol/L

Plugging in the values into the equation we derived earlier:

V1 = (0.100 mol/L * 1.00 L) / 12.50 mol/L
= 0.008 L

Therefore, you will need 0.008 liters (or 8.00 mL) of the concentrated NaOH solution to make 1.00L of a 0.100M NaOH solution.

Use the dilution formula

mL1 x M1 = mL2 x M2

The biggest problem here is that you don't have the M of the NaOH. So change grams NaOH to mols (mols = g/molar mass) and M = mol/L solution then plug into the dilution formula.

L=8