Question

016 (part 1 of 2) 10.0 points

A speedboat increases in speed from 17.9 m/s
to 31.8 m/s in a distance 188 m.
Find the magnitude of its acceleration.

Answer 1

Vo = 17.9 m/s.

V = 31.8 m/s.
d = 188 m.

V^2 = Vo^2 + 2a*d
a = (V^2-Vo^2)/2d = (31,8^2-17.9^2)/376
= 1.84 m/s^2.