find the mass of water(H2O) needed to react with 150 grams of potassium(K)
2K + 2H2O ==> 2KOH + 2H2
mols K = grams/molar mass = ?
Using the coefficients in the balanced equation, convert mols K to mols H2O.
That's ? mols K x (2 mols H2O/2 mol K) = ? mols K x 2/2 = ? mols H2O
Now convert mols H2O to grams. g = mols x molar mass.
How do I get the number of moles of H2O
See your other posts.
To find the mass of water (H2O) needed to react with 150 grams of potassium (K), we need to determine the stoichiometry of the reaction between potassium and water.
The balanced chemical equation for the reaction is:
2 K + 2 H2O -> 2 KOH + H2
From the equation, we can see that 2 moles of potassium (K) react with 2 moles of water (H2O).
To find the mass of water needed, we need to calculate the molar mass of water and convert the mass of potassium (K) to moles.
The molar mass of water (H2O) is calculated as follows:
1 mole of hydrogen (H) = 1.007 grams (atomic mass of hydrogen)
1 mole of oxygen (O) = 16.00 grams (atomic mass of oxygen)
So, the molar mass of water (H2O) = (2 x 1.007) + 16.00 = 18.015 grams
Now, we can calculate the moles of potassium (K) using its molar mass.
Molar mass of potassium (K) = 39.10 grams/mol
Moles of potassium (K) = Mass of potassium (K) / Molar mass of potassium (K)
Moles of potassium (K) = 150 grams / 39.10 grams/mol
Once we have the moles of potassium (K), we can determine the moles of water needed using the stoichiometry of the reaction.
From the balanced equation, we know that 2 moles of potassium (K) react with 2 moles of water (H2O).
Therefore, moles of water (H2O) needed = Moles of potassium (K)
Finally, we can calculate the mass of water (H2O) needed using its molar mass.
Mass of water (H2O) needed = Moles of water (H2O) needed x Molar mass of water (H2O)
By following these steps, you can find the mass of water needed to react with 150 grams of potassium.