what mass of precipitate will form if 1.5L of concentrated pb(clo3)2 is mixed with .55L of.190 M NaI
Pb(ClO3)2 + NaI ==> PbI2 + 2NaClO3
Concentrated is a relative term and doesn't mean anything to me.
To determine the mass of the precipitate that will form when 1.5L of concentrated Pb(ClO3)2 is mixed with 0.55L of 0.190 M NaI, we need to follow a few steps:
1. Write the balanced chemical equation: The balanced equation for the reaction between Pb(ClO3)2 and NaI is as follows:
2Pb(ClO3)2 + 4NaI → 2PbI2 + 4NaClO3
This equation shows that two moles of Pb(ClO3)2 react with four moles of NaI to form two moles of PbI2 and four moles of NaClO3.
2. Determine the limiting reagent: To determine the limiting reagent, we need to compare the number of moles of Pb(ClO3)2 and NaI present in the given volumes.
For Pb(ClO3)2:
Molarity (M) = moles/volume (L)
moles = M x volume
Given:
Concentration of Pb(ClO3)2 = Concentrated (no specific value given)
Volume of Pb(ClO3)2 = 1.5 L
Since we don't have the specific concentration, we cannot calculate the moles unless we have further information about the concentration.
For NaI:
Molarity (M) = 0.190 M
Volume of NaI = 0.55 L
moles of NaI = 0.190 M x 0.55 L
3. Calculate the moles of the limiting reagent: As we don't have the specific concentration of Pb(ClO3)2, we cannot determine the number of moles. If you have the concentration of Pb(ClO3)2 or any additional information, you can plug it into the formula: moles = M x volume.
4. Use the stoichiometry from the balanced chemical equation to determine the moles of precipitate formed: From the balanced chemical equation, we see that it takes two moles of Pb(ClO3)2 to produce two moles of PbI2. Therefore, the moles of PbI2 formed will be equal to the moles of the limiting reagent.
5. Convert moles of PbI2 to mass: To convert the moles of PbI2 to mass, we need the molar mass of PbI2. The molar mass of PbI2 is determined by adding the atomic masses of lead (Pb) and iodine (I) in the compound.
Finally, to obtain the mass of the precipitate formed, calculate:
Mass = Moles of PbI2 x Molar mass of PbI2
Without the specific concentration of Pb(ClO3)2, we cannot provide an exact answer to this question.