Li+Cl=>LiCl ionic bonding atoms valence electrons electron transfer from/ to each atom and ions formed in the product??
To understand the electron transfer and ions formed in the reaction Li + Cl -> LiCl, let's break down the steps:
1. Li (lithium) has one valence electron, while Cl (chlorine) has seven valence electrons.
2. Since both Li and Cl want to achieve stable electron configuration, which is a full outer shell, Li wants to lose its one valence electron, and Cl wants to gain one electron.
3. During the reaction, Li loses one electron and becomes Li+ (a cation) because it now has one less electron than protons.
4. Cl gains one electron and becomes Cl- (an anion) because it now has one more electron than protons.
5. The electron transfer results in the formation of an ionic bond between Li+ and Cl-.
6. The final product is LiCl, which is an ionic compound made up of Li+ cations and Cl- anions. The ionic bonding between these ions holds the compound together.
To determine the ion charges and ions formed in the product of the ionic bonding between Li and Cl, we need to consider the valence electrons and the process of electron transfer.
Step 1: Determine the valence electrons of each atom:
- Lithium (Li) is in Group 1, so it has 1 valence electron.
- Chlorine (Cl) is in Group 7, so it has 7 valence electrons.
Step 2: Determine the electron transfer:
- Lithium (Li) wants to lose one valence electron to achieve a stable electron configuration.
- Chlorine (Cl) wants to gain one electron to achieve a stable electron configuration.
Since the valence electron of Li and the number of electrons needed for Cl to complete its octet match, it results in a one-to-one electron transfer. Lithium donates its one valence electron to chlorine, and as a result, both atoms achieve a stable electron configuration.
Step 3: Determine the ions formed in the product:
- Lithium (Li) loses one electron and forms a cation (Li+).
- Chlorine (Cl) gains one electron and forms an anion (Cl-).
So, in the product (LiCl), a lithium cation (Li+) and a chloride anion (Cl-) are formed as a result of ionic bonding between Li and Cl.