lim {x-3}/(x^2-9)
x->3
( I used {} to show absolute value)
Find the limit if there is one.
(x-3) / [ (x-3)(x+3) = 1/(x+3)
so when x is 3
1/6
x->3
( I used {} to show absolute value)
Find the limit if there is one.
so when x is 3
1/6