please HELP!!


mass of magnesium chloride =.2
mass of chlorine in magnesium chloride =.1

A)moles of magnesium?
B)moles of chlorine?
C)moles of magnesium divided by the smaller number of moles?
D)moles of chlorine divided by the smaller number of moles?
E)experimental empirical formula of magnesium chloride?
F) true empirical formula of magnesium chloride?

A. mols Mg = grams/molar mass = aprox 0.0082 but you need to redo all of these since I've estimated.

B. mols Cl2 = grams/molar mass BUT mols Cl ion is grams/atomic mass or approx 0.0028

C. 0.0082/0.0028 = 2.93
D. 0.0028/0.0028 = 1.00
E. D is rounded to 1.00; C is rounded to 3.00 empricial formula is Mg3Cl
F. MgCl2.

A) To find the moles of magnesium (Mg), you need to divide the mass of magnesium chloride (MgCl2) by the molar mass of Mg. The molar mass of Mg is 24.31 g/mol. Therefore, the moles of magnesium can be calculated as follows:

moles of Mg = mass of MgCl2 / molar mass of Mg
= 0.2 g / 24.31 g/mol

B) To determine the moles of chlorine (Cl), you divide the mass of chlorine in magnesium chloride by the molar mass of chlorine (Cl). The molar mass of Cl is 35.45 g/mol. Hence, the moles of chlorine can be found using the formula:

moles of Cl = mass of chlorine / molar mass of Cl
= 0.1 g / 35.45 g/mol

C) To calculate moles of magnesium divided by the smaller number of moles, compare the moles of magnesium and chlorine calculated in the previous steps and take the smaller value. Let's call this value "x".

moles of Mg divided by the smaller number of moles = moles of Mg / x

D) To calculate moles of chlorine divided by the smaller number of moles, compare the moles of magnesium and chlorine calculated earlier and take the smaller value. We'll call this value "x".

moles of Cl divided by the smaller number of moles = moles of Cl / x

E) To determine the experimental empirical formula of magnesium chloride, divide the moles of magnesium and chlorine by their respective smaller number of moles. You can then convert these ratios to whole numbers.

Experimental empirical formula = (moles of Mg / x) : (moles of Cl / x)

F) To determine the true empirical formula of magnesium chloride, we need additional information such as the actual ratio of moles between magnesium and chlorine. Without this information, we cannot determine the true empirical formula.

Sure, I can help you with that! To find the answers to these questions, we need to use the concept of moles and molar mass. The molar mass is the mass of one mole of a substance, and it is calculated by adding up the atomic masses of all the atoms in the formula.

In this case, we know the mass of magnesium chloride is 0.2 g and the mass of chlorine in magnesium chloride is 0.1 g.

A) Moles of magnesium:
To calculate the moles of magnesium, we need to know the molar mass of magnesium. The atomic mass of magnesium is approximately 24.31 g/mol. We can use the formula:

moles = mass / molar mass

moles of magnesium = 0.2 g / 24.31 g/mol

B) Moles of chlorine:
To calculate the moles of chlorine, we need to know the molar mass of chlorine. The atomic mass of chlorine is approximately 35.45 g/mol. We can use the same formula:

moles of chlorine = 0.1 g / 35.45 g/mol

C) Moles of magnesium divided by the smaller number of moles:
To find the smaller number of moles, compare the values obtained in parts A and B. Then, divide the moles of magnesium by the smaller number of moles.

D) Moles of chlorine divided by the smaller number of moles:
To find the smaller number of moles, compare the values obtained in parts A and B. Then, divide the moles of chlorine by the smaller number of moles.

E) Experimental empirical formula of magnesium chloride:
The empirical formula represents the simplest whole number ratio of elements in a compound. To find it, divide the moles of each element by the smaller number of moles obtained in parts C and D. If the result is not a whole number, multiply all the numbers by the same factor to obtain the simplest whole number ratio.

F) True empirical formula of magnesium chloride:
To find the true empirical formula, we also need to consider the valence of the elements. Since magnesium has a valence of 2 and chlorine has a valence of 1, the true empirical formula of magnesium chloride will be MgCl2.

I hope this explanation helps you in solving the problem!