To push a 16 kg crate up a frictionless incline, angled at 32° to the horizontal, a worker exerts a force of 108.0 N, parallel to the incline. As the crate slides 1.50 m, how much work is done on the crate by the worker's applied force?

To calculate the work done on the crate by the worker's applied force, you can use the formula:

Work = Force * Distance * cos(theta)

Where:
- Work is the amount of work done (in joules)
- Force is the applied force (in newtons)
- Distance is the distance over which the force is applied (in meters)
- theta is the angle between the applied force and the direction of displacement (in degrees)

In this case, the applied force is 108.0 N, the distance is 1.50 m, and the angle theta is 32°.

So, the work done on the crate can be calculated as:

Work = 108.0 N * 1.50 m * cos(32°)

Now, let's calculate the cosine of 32°:

cos(32°) ≈ 0.8480

Substituting the values into the equation:

Work = 108.0 N * 1.50 m * 0.8480

Work ≈ 163.224 J

Therefore, the amount of work done on the crate by the worker's applied force is approximately 163.224 joules.