Question

There are two chords AB and AC in a circle.[AB]=10cm, [CD]=8cm and the radius of the circle is 12cm.what is the distance of each chord from the centre of the ccircle?

Answer 1

Answers

Answer 2

Draw a diagram of a chord in a circle.

In a circle of radius r, a chord of length 2x forms two right triangles where the distance d from the center is found using

d^2+x^2 = r^2

Answer 3

anwer

Answer 4

the diagram

Answer 5

I need answer

Answer 6

[AI-generated answer — Explain Bot]

To find the distance of each chord from the center of the circle, we can use the following formula:

Distance from center = √(radius² - (chord length/2)²)

Let's calculate the distance of chord AB from the center:

Distance of AB from center = √(12² - (10/2)²)
= √(144 - 25)
= √119
≈ 10.92 cm

Now, let's calculate the distance of chord AC from the center:

Distance of AC from center = √(12² - (8/2)²)
= √(144 - 16)
= √128
≈ 11.31 cm

Therefore, the distance of chord AB from the center of the circle is approximately 10.92 cm, and the distance of chord AC from the center is approximately 11.31 cm.