A camera falls from a blimp that is 744 m
above the ground and rising at a speed of
15.5 m/s.
Find the maximum height reached by the
camera with respect to the ground. The acceleration of gravity is 9.8 m/s^2.
Answer in units of m.
PLEASE HELP SOON
h = ho + -(Vo^2)/2g
h = 744 + -(15.5^2)/-19.6 = 756.3 m
To find the maximum height reached by the camera, we can use the kinematic equation for vertical motion:
final velocity squared = initial velocity squared + 2 * acceleration * displacement
First, let's determine the initial velocity of the camera. Since it falls from a blimp, we can assume its initial velocity is 0 m/s, as it is only influenced by the gravitational acceleration.
Next, we can calculate the displacement of the camera when it reaches its maximum height. We know that the camera falls from a height of 744 m, so the displacement would be equal to the negative value of the initial height because it is going upwards. Therefore, the displacement would be -744 m.
Now we can plug in the values into the kinematic equation:
final velocity squared = 0 squared + 2 * (-9.8) * (-744)
Simplifying:
final velocity squared = 2 * 9.8 * 744
final velocity squared = 14597.6
Taking the square root of both sides:
final velocity ≈ 120.97 m/s
However, the final velocity at the maximum height is 0 m/s because the camera momentarily stops before starting to fall again. This is the point of maximum height.
So, the maximum height reached by the camera is approximately 744 m.
Therefore, the maximum height reached by the camera with respect to the ground is 744 m.