I was way off on the other problem.
But I see how you got the answer.
Last one...thanks i'm learning more
here thn class
What is the sum of the coefficients (including “1”) of the following reaction?
Sodium sulfate + calcium hydroxide ???
Write the equation (double displacement)
Na2SO4 + Ca(OH)sub>2 >>>> CaSO4 + 2NaOH
check to see if it is balanced,
Then add them.
thanks you very much.
i do not understand Ca(OH)sub >2
typo, sorry:
Na2SO4 + Ca(OH)2 >>>> CaSO4 + 2NaOH
awesome...thank you very much!!!
To find the sum of the coefficients in the given reaction, we need to first write the balanced equation. Here's the equation you provided:
Na2SO4 + Ca(OH)2 >>>> CaSO4 + 2NaOH
To balance the equation, we need to ensure that the same number of each element appears on both sides of the equation. Let's balance it step by step:
Na2SO4 + Ca(OH)2 >>>> CaSO4 + 2NaOH
On the left side, we have 2 sodium atoms (Na), 1 sulfur atom (S), 4 oxygen atoms (O), 1 calcium atom (Ca), 2 hydrogen atoms (H), and 2 oxygen atoms (O) again.
On the right side, we have 1 calcium atom (Ca), 1 sulfur atom (S), 4 oxygen atoms (O), 2 sodium atoms (Na), 1 hydrogen atom (H), and 1 oxygen atom (O).
To balance the equation, we need to adjust the coefficients in front of each compound. Here's the balanced equation:
Na2SO4 + Ca(OH)2 >>>> CaSO4 + 2NaOH
Now, let's find the sum of the coefficients (including "1") in the balanced equation:
2 + 1 + 4 + 1 + 2 + 1 + 2 = 13
So, the sum of the coefficients (including "1") in the given reaction is 13.
I hope this explanation helps you understand how to solve this problem. Let me know if you have any further questions!