How would you prepare 165 mL of a 0.976 M NaOH solution, starting with a 6.36 M stock solution?
Volume of solution needed?
Volume of water needed?
mL1 x M1 = mL2 x M2
165 x 0.976 = mL2 x 6.36
Solve for mL2, place that in a container and add enough water to make 165 mL.