How far will a motorcycle driven by Emily travel, if it is initially moving at 14.8 ft/s and accelerates uniformly at 11.3 ft/s2 for 6.6 seconds?
My teacher never gave us equations to use when solving this king of problem.
http://hyperphysics.phy-astr.gsu.edu/hbase/mot.html
You want the box labeled:
"Description of motion in one dimension"
here for example
Vo = 14.8
a = 11.3 ft/s^2
t = 6.6 sd
v = Vo + a t
so
v = 14.8 + 11.3 * 6.6
= 89.4 feet/second
To determine the distance traveled by a motorcycle, you can use the formula:
distance = initial velocity * time + (1/2) * acceleration * time^2
Now, let's break down the problem and find the solution step by step:
1. Given:
- Initial velocity (u) = 14.8 ft/s
- Acceleration (a) = 11.3 ft/s^2
- Time (t) = 6.6 seconds
2. Plug in the values into the formula:
distance = (14.8 * 6.6) + (1/2) * 11.3 * (6.6)^2
3. Solve the equation step by step:
First, calculate (1/2) * 11.3 * (6.6)^2:
= 0.5 * 11.3 * 43.56
= 242.958
Then, multiply the initial velocity by the time:
= 14.8 * 6.6
= 97.68
Finally, add the two results together to find the distance traveled:
distance = 97.68 + 242.958
= 340.638 ft
Therefore, Emily's motorcycle will travel approximately 340.638 feet.