When a skydiver jumps from an airplane, the distance d in feet the diver falls in t seconds before opening the parachute is given by the formula d=16t^2. The formula assumes that there is no air resistance. Find the time it takes a skydiver to fall 1,551 ft before opening the parachute. Round to the nearest tenth.
A. 9.7 s
B. 9.8 s
C. 9.9 s
D. 2.5 s
Is the answer D?
This is from a website, because I can't explain it very well. With the below information, it makes me think the answer is B. Here's the information provided from a website with a few modifications to it to be more organized:
"
16t^2 = 1551
16t^2/ 16 = 1551/16
t^2 = 96.93
t = 9.8 sec
"
I hope this helps! :)
To find the time it takes for a skydiver to fall a given distance before opening the parachute, we can substitute the given distance into the formula and solve for t. Let's do that step by step:
Given: d = 1551 ft
Formula: d = 16t^2
Substituting the value of d into the formula, we get:
1551 = 16t^2
Now, let's rearrange the equation to solve for t. Divide both sides by 16:
t^2 = 1551/16
Taking the square root of both sides to isolate t, we have:
t = √(1551/16)
Evaluating this, we find:
t ≈ 9.849
Rounding this to the nearest tenth, we get approximately 9.8.
Therefore, the time it takes a skydiver to fall 1,551 ft before opening the parachute is approximately 9.8 seconds.
So the correct answer is B. 9.8 s.