how many moles of oxygen gas are required to react with 4.0 moles of Mg?

2 Mg (s) + O2(g) → 2 MgO (s)

4 mols Mg x (1 mol O2/2 mol Mg) = 4*1/2 = ?

2.0

2.0

To determine how many moles of oxygen gas (O2) are required to react with 4.0 moles of magnesium (Mg), we can use the balanced chemical equation provided:

2 Mg (s) + O2(g) → 2 MgO (s)

From the equation, we can see that two moles of magnesium react with one mole of oxygen gas to produce two moles of magnesium oxide (MgO). Therefore, the mole ratio between magnesium and oxygen gas is 2:1.

Since we have 4.0 moles of magnesium, we need to determine how many moles of oxygen gas are required using the mole ratio:

(4.0 moles Mg) x (1 mole O2 / 2 moles Mg) = 2.0 moles O2

Therefore, 2.0 moles of oxygen gas are required to react with 4.0 moles of magnesium.