How many aluminum atoms are in 3.78 g\rm g of aluminum?
8.44⋅10^22 Al atoms
There are 6.022 atoms in 1 mol atoms and 1 mol atoms Al weigh 26.98 grams.
To calculate the number of aluminum atoms in a given mass of aluminum, you can use the concept of atomic mass and Avogadro's number.
1. Determine the molar mass of aluminum:
The atomic mass of aluminum is approximately 27 g/mol.
2. Calculate the number of moles of aluminum:
Moles = Mass / Molar mass
Moles = 3.78 g / 27 g/mol
3. Calculate the number of aluminum atoms:
Number of atoms = Moles * Avogadro's number
Number of atoms = Moles * 6.022 x 10^23 atoms/mol
To find the number of aluminum atoms in a given mass of aluminum, you need to use the concept of molar mass and Avogadro's number.
1. First, determine the molar mass of aluminum. The atomic mass of aluminum is approximately 26.98 g/mol.
2. Next, use this molar mass to calculate the number of moles of aluminum in the given mass. The formula to calculate the number of moles is:
Moles = Mass (g) / Molar mass (g/mol)
Thus, for 3.78 g of aluminum, the number of moles can be calculated as:
Moles = 3.78 g / 26.98 g/mol
Simplifying the calculation, Moles ≈ 0.14 mol
3. Finally, use Avogadro's number, which is approximately 6.022 x 10^23 atoms/mol, to find the number of aluminum atoms in the given mass. Multiply the number of moles by Avogadro's number:
Number of aluminum atoms = Moles × Avogadro's number
Number of aluminum atoms = 0.14 mol × 6.022 x 10^23 atoms/mol
The final result is approximately 8.431 x 10^22 aluminum atoms in 3.78 g of aluminum.