Start from 110 feet away, a person on a bicycle rides toward a checkpoint and then passes it. The rider is traveling at a constant of 30m feet per second. The distance between the bicycle and the checkpoint is given by the equation d=(110-30t). At what times is the bike 40 feet away from the checkpoint?
To find the time when the bike is 40 feet away from the checkpoint, we need to equate the distance between the bicycle and the checkpoint to 40 feet.
Given the equation:
d = 110 - 30t
We substitute the distance, d, with 40:
40 = 110 - 30t
Now, we can solve for t by manipulating the equation:
-30t = 40 - 110
-30t = -70
Divide both sides by -30:
t = (-70) / (-30)
t = 7/3
Therefore, the bike is 40 feet away from the checkpoint at t = 7/3 seconds.
To find the times when the bike is 40 feet away from the checkpoint, we need to set up an equation using the given distance formula and solve for t (time).
The distance between the bike and the checkpoint is given by the equation: d = 110 - 30t
We want to find the times when the bike is 40 feet away from the checkpoint, so we set d equal to 40 and solve for t:
40 = 110 - 30t
To solve for t, we need to isolate the variable t on one side of the equation. Let's do that:
30t = 110 - 40
Combine like terms:
30t = 70
Now, divide both sides of the equation by 30 to solve for t:
t = 70 / 30
t = 7/3 or approximately 2.333 seconds
Therefore, the bike is 40 feet away from the checkpoint at approximately 2.333 seconds.
hmmm that would be when
110-30t = 40
so, just solve for t.
Also, lose the "m".