Determine how many kg of benzoic acid would dissolve in 1.00 Liter of water at 50 degrees C?
My work:
1.00/50C X 1000g/1L X .001kg/1g= 1kg/50C
You haven't posted the solubility of benzoic acid at 50C and without that I can't check your work; however, on the surface 1 kg seems too high to me.
To determine how many kg of benzoic acid would dissolve in 1.00 liter of water at 50 degrees Celsius, we need to know the solubility of benzoic acid at that temperature. The solubility of benzoic acid in water varies with temperature. Is there any solubility data provided for benzoic acid at 50 degrees Celsius?
To determine the number of kilograms of benzoic acid that would dissolve in 1.00 liter of water at 50 degrees Celsius, you typically need to consult a solubility table or experimentally determined values for benzoic acid in water at that temperature.
Solubility is usually given in units of grams per liter (g/L), so we need to convert from liters to grams. Since the density of water is approximately 1 gram per milliliter (g/mL), we can assume that 1 liter of water is equal to 1000 grams (g).
Next, we need to convert from grams to kilograms because the question asks for kilograms of benzoic acid. Since there are 1000 grams in a kilogram (kg), we divide the amount in grams by 1000 to convert to kilograms.
The calculation you showed, 1.00/50°C x 1000g/1L x 0.001kg/1g = 1kg/50°C, seems to be an attempt to convert liters to kilograms, but it is not a correct calculation for determining the solubility of benzoic acid in water.
To find the solubility of benzoic acid in water at 50 degrees Celsius, you would typically need to consult a solubility table or an experimental study and look up the specific value for benzoic acid at that temperature.