When 2016 J of heat energy is added to 49.5 g of ethanol, C2H6O, the temperature increases by 16.6 °C. Calculate the molar heat capacity of C2H6O.
49.5g = 2.98mols
C=q/n*temperature change in Celsius
2016/2.98*16.6
woah there, watch out
molar mass of 46.08 g/mol
2(12.01) + 6(1.01) + 16 = 46.08 g
thus,
49.5 g * (1 mol/46.08 g) ≈ 1.07 mol
oops, typo on my part second line should say:
molar mass of "ethanol should be" 46.08 g/mol
To calculate the molar heat capacity (C) of ethanol (C2H6O), you can use the formula:
C = q / (n × ΔT)
Where:
C = Molar heat capacity (in J/mol·°C)
q = Heat energy added (in J)
n = Number of moles of ethanol (in mol)
ΔT = Temperature change (in °C)
Given:
Heat energy added (q) = 2016 J
Mass of ethanol (C2H6O) = 49.5 g
Molar mass of ethanol (C2H6O) = 46.07 g/mol
First, calculate the number of moles (n) using the mass of ethanol:
n = Mass / Molar mass
n = 49.5 g / 46.07 g/mol
n = 1.074 mol (rounded to 3 decimal places)
Next, calculate the molar heat capacity (C) using the formula:
C = q / (n × ΔT)
C = 2016 J / (1.074 mol × 16.6 °C)
C ≈ 116.011 J/mol·°C (rounded to 3 decimal places)
Therefore, the molar heat capacity of ethanol (C2H6O) is approximately 116.011 J/mol·°C.