can anyone help me with that question

what is the domain of log(log(x)the base is 0.2)

Since the domain of log(x) is x > 0,

we need log(x) > 0
that is, 0 < x < 0.2

You can see this reflected in the graph found below. The domain is where the imaginary part is zero.

http://www.wolframalpha.com/input/?i=log_.2%28log_.2%28x%29%29

the question was log(log_.2(x))

the base of the first log is 10 then the base of the second log which is inside the brackets is 0.2

Of course, I can help you with that question!

To find the domain of the function f(x) = log(log(x)) with a base of 0.2, we need to consider the restrictions on the input, x.

The domain of a logarithmic function is determined by the values that do not cause the function to be undefined. In this case, there are two things to consider:

1. The argument of the outer logarithm (log(x)) must be positive.
Since we cannot take the logarithm of a non-positive number, the argument of the outer logarithm, x, must be greater than 0.

2. The argument of the inner logarithm (log(x)) must be positive.
The argument of the inner logarithm, log(x), must be greater than 0 because the base of 0.2 does not allow for negative values.

To summarize, the domain of f(x) = log(log(x)) with a base of 0.2 is x > 0.

Therefore, the solution is all real numbers greater than 0.