Question

amy made bags filled with M&M's and skittles. She used 48 M&M's and 30 skittles. she used the same number of each candy in every bag. what is the maximum number of bags she could make?

Answer 1

What is the greatest common factor of 30 and 48?

Answer 2

10

Answer 3

10 is not a factor of 48.

http://www.mathsisfun.com/greatest-common-factor.html

Answer 4

is it 240?

Answer 5

No.

Answer 6

is it 6?

Answer 7

[AI-generated answer — Explain Bot]

To find the maximum number of bags Amy could make, we need to determine the greatest common divisor (GCD) of the given numbers of M&M's and Skittles. The GCD represents the largest number that divides both numbers evenly.

The GCD of 48 and 30 can be found through various methods, such as prime factorization, listing common factors, or using the Euclidean algorithm. One straightforward way is to list the factors of both numbers:

Factors of 48: 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
Factors of 30: 1, 2, 3, 5, 6, 10, 15, 30

By examining the lists, we find that the common factors are 1, 2, 3, and 6. The largest common factor is 6, which means 6 is the GCD of 48 and 30.

Since Amy wants to use the same number of each candy in every bag, the number of bags she can make is equal to the GCD of 48 and 30, which is 6. Therefore, the maximum number of bags Amy could make is 6.