I am having trouble with functions the question is to find the indicated outputs for f(x)=4x^2-2x

f(0)
f(-1)
f(2)

Can someone please explain?

f (0) = 4 * 0 * 0 - 2 * 0

= 0

f(-1) = 4 *-1*-1 - 2*-1
= 4 + 2
= 6

f(2) = 4*2*2 - 2*2
= 16 - 4
=12

Sure! To find the indicated outputs for the function f(x) = 4x^2 - 2x, you simply need to substitute the given values into the function and calculate the result.

Let's start with f(0):
To find f(0), we replace every occurrence of x in the function with 0:
f(0) = 4(0)^2 - 2(0)
= 4(0) - 2(0)
= 0 - 0
= 0

Therefore, f(0) = 0.

Now, let's move on to f(-1):
To find f(-1), we replace every occurrence of x in the function with -1:
f(-1) = 4(-1)^2 - 2(-1)
= 4(1) + 2
= 4 + 2
= 6

Therefore, f(-1) = 6.

Lastly, let's calculate f(2):
To find f(2), we substitute x = 2 into the function:
f(2) = 4(2)^2 - 2(2)
= 4(4) - 4
= 16 - 4
= 12

So, f(2) = 12.

Therefore, the indicated outputs for f(x) = 4x^2 - 2x are: f(0) = 0, f(-1) = 6, and f(2) = 12.