what volume of 0.150M Li2Sr solution is required to completely react with 130ml of 0.150M Co(NO3)2

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130 mL

To determine the volume of the Li2Sr solution required to completely react with the Co(NO3)2 solution, we can use the stoichiometry of the balanced equation between the two reactants.

The balanced equation for the reaction between Li2Sr and Co(NO3)2 is:

2 Li2Sr + 3 Co(NO3)2 → 2 Sr(NO3)2 + 3 Co

From the equation, we can see that 2 moles of Li2Sr react with 3 moles of Co(NO3)2.

Step 1: Calculate the number of moles of Co(NO3)2

Moles of Co(NO3)2 = Concentration (M) × Volume (L)
= 0.150 M × 0.130 L
= 0.0195 moles

Step 2: Use the stoichiometry to determine the required volume of Li2Sr solution.

From the balanced equation, we can see that 3 moles of Co(NO3)2 react with 2 moles of Li2Sr. Therefore:

2 moles Li2Sr = 3 moles Co(NO3)2
1 mole Li2Sr = (3/2) moles Co(NO3)2
moles Li2Sr = (3/2) × 0.0195 moles Co(NO3)2

Step 3: Calculate the volume of Li2Sr solution using its concentration.

Volume (L) = Moles / Concentration

Volume of Li2Sr solution = [(3/2) × 0.0195 moles Co(NO3)2] / 0.150 M

Now, you can calculate the volume of the Li2Sr solution using the given values.