Susan has a balance of 110 dollars in her school lunch account and she spends 6 dollars per day for lunch. Her sister Evelyn has $83 in her account and she spends 4 dollar per day for lunch. Write and solve an inequality that shows in how many days will Susans lunch account balance be less than Evelyn?

110+6x<83+4x

Would the inequality be 110+6x<83+4x

13.5 days?

x>-13.5 is the answer

I meant to say x>13.5

ayeeeeeeee

To write an inequality that shows how many days Susan's lunch account balance will be less than Evelyn's, we need to represent the amount of money Susan has left after a certain number of days (110 + 6x, where x is the number of days) and the amount of money Evelyn has left after the same number of days (83 + 4x, where x is the number of days).

The inequality can be expressed as:

110 + 6x < 83 + 4x

Now, to solve the inequality, we'll isolate the variable x:

110 - 83 < 4x - 6x
27 < -2x

To get rid of the negative coefficient, we divide both sides of the inequality by -2. However, when dividing by a negative number, we need to flip the inequality sign:

27/(-2) > x
-13.5 > x

Therefore, Susan's lunch account balance will be less than Evelyn's for any number of days greater than 13.5. Since we can't have a fraction of a day, we round up to the nearest whole number, which means Susan's account balance will be less than Evelyn's after 14 days.