When a jet lands on an aircraft carrier, a hook on the tail of the plane grabs a wire that quickly brings the plane to a halt before it overshoots the deck. In a typical landing, a jet touching down at 240 km/h is stopped in a distance of 95 m. What is the magnitude of the jet's acceleration as it is brought to rest?

Vo = 240km/h = 240,000m/3600s = 66.7 m/s

V^2 = Vo^2 + 2a*d
a = (V^2-Vo^2)/2d = (0-(66.7^2))190 =
23.42 m/s^2.

Whoa, we've got a jet in need of a pit stop! Alright, let me calculate the magnitude of its acceleration.

To find the acceleration, we need to use the equation of motion:

v^2 = u^2 + 2as

Where:
v = final velocity (0 m/s, because the jet comes to a halt)
u = initial velocity (240 km/h)
a = acceleration (what we're looking for)
s = distance (95 m)

Now, let's do some unit conversion first. 240 km/h can be converted to m/s by dividing it by 3.6 (since 1 km/h = 1000 m/3600 s). That gives us an initial velocity of approximately 66.67 m/s.

Plugging the values into the equation, we get:

0^2 = (66.67)^2 + 2a(95)

Simplifying that equation, we find:

0 = 4444.44 + 190a

Rearranging to solve for a:

a = -4444.44 / 190

Calculating that, we find:

a ≈ -23.39 m/s^2

So, the magnitude of the jet's acceleration, as it comes to rest, is approximately 23.39 m/s^2. That's some serious braking power!

To find the magnitude of the jet's acceleration, we can use the equation of motion:

v^2 = u^2 + 2as

Where:
v is the final velocity (zero in this case, as the jet is brought to rest)
u is the initial velocity (240 km/h, which we need to convert to m/s)
a is the acceleration (what we need to find)
s is the displacement (95 m)

First, let's convert the initial velocity from km/h to m/s:
1 km/h = 1000 m/3600 s ≈ 0.2778 m/s

So, the initial velocity (u) is 240 km/h * 0.2778 m/s ≈ 66.67 m/s.

The equation now becomes:
0^2 = (66.67 m/s)^2 + 2a(95 m)

Simplifying this equation, we have:
0 = 66.67^2 + 2a(95)

Rearranging and solving for a, we get:
2a(95) = -(66.67^2)
a = -(66.67^2) / (2 * 95)

Using a calculator, we can evaluate this expression to find:
a ≈ -23.36 m/s^2

The magnitude of acceleration is always positive, so in this case, we can take the absolute value:
|a| ≈ 23.36 m/s^2

Therefore, the magnitude of the jet's acceleration as it is brought to rest is approximately 23.36 m/s^2.

-23.4