Describe how to make 450mL of a 1.15% solution of CuSO4
By mass, by volume, by what. I'll assume by mass.
[(x)/(g soln)]*100 = 1.15
Solve for x = grams solute. That's about 5 g but you need a more accurate number than that.
Dissolve approx 5 g in approx 445 g H2O. Remember to confirm the numbers with better accuracy.