The volume of a 3.60L sample of gas at 27degrees Celsius is reduced at constant pressure of 3.00L. What is the final temperature?
(V1/T1) = (V2/T2)
Remember that T must be in kelvin.
T2 = 300K(3.00L/3.60L)
= 250K or -27degrees Celsius
To find the final temperature, we can use the formula:
(V1/T1) = (V2/T2)
Where:
V1 = Initial volume
T1 = Initial temperature
V2 = Final volume
T2 = Final temperature
Given:
V1 = 3.60 L
T1 = 27°C = 27 + 273.15 = 300.15 K
V2 = 3.00 L
Substituting the given values into the formula, we have:
(3.60 L / 300.15 K) = (3.00 L / T2)
Now, let's solve for T2.
Cross-multiplying the equation:
3.60 L * T2 = 3.00 L * 300.15 K
Dividing both sides of the equation by 3.60 L:
T2 = (3.00 L * 300.15 K) / 3.60 L
Canceling out the units of liters gives us:
T2 ≈ 249.75 K
Therefore, the final temperature is approximately 249.75 Kelvin.