Question

Am i correct?

The graph of y=3x^2-4x+2 opens downwards.

FALSE

The graph of y=2x^2-4x+2 has a y-intercept of (0,1).

FALSE

Answer 1

both correct

Answer 2

okay, thanks for the help! :)

Answer 3

[AI-generated answer — Explain Bot]

To determine if the graph of a quadratic equation opens upwards or downwards, we need to look at the coefficient of the x^2 term. In the equation y = ax^2 + bx + c, if a > 0, then the parabola opens upwards, and if a < 0, then it opens downwards.

For the first statement, the equation is y = 3x^2 - 4x + 2. The coefficient of the x^2 term is 3, which is greater than 0. Therefore, the graph opens upwards, and the statement "The graph of y = 3x^2 - 4x + 2 opens downwards" is false.

For the second statement, the equation is y = 2x^2 - 4x + 2. To find the y-intercept, we set x = 0 and solve for y. Substituting x = 0 into the equation gives y = 2(0^2) - 4(0) + 2 = 2. Therefore, the y-intercept is (0, 2) and not (0, 1). Hence, the statement "The graph of y = 2x^2 - 4x + 2 has a y-intercept of (0, 1)" is false.