While the pressure of 1.40L of gas is kept constant, its temperature is increased from 27 degrees Celcius to 177 degrees Celcius, How do I calculate the new volume?
Note the correct spelling of celsius.
Use (V1/T1) = (V2/T2)
Remember T must be in kelvin
V2=1.4L (450K/300K)=2.1L
I agree.
To calculate the new volume of the gas when the temperature is increased from 27 degrees Celsius to 177 degrees Celsius, you can use the combined gas law equation:
(P1 * V1) / T1 = (P2 * V2) / T2
where:
P1 is the initial pressure of the gas (constant)
V1 is the initial volume of the gas
T1 is the initial temperature of the gas
P2 is the final pressure of the gas (constant)
V2 is the final volume of the gas (unknown)
T2 is the final temperature of the gas
In this case, the pressure is kept constant, so P1 = P2.
Also, we know the initial volume (V1 = 1.40 L) and initial temperature (T1 = 27 degrees Celsius). We want to calculate the final volume (V2) when the final temperature is 177 degrees Celsius.
First, let's convert the temperatures from Celsius to Kelvin, as Kelvin is the absolute temperature scale:
T1 (initial temperature) = 27 + 273.15 = 300.15 K
T2 (final temperature) = 177 + 273.15 = 450.15 K
Now, we can rearrange the combined gas law equation to solve for V2:
V2 = (P1 * V1 * T2) / (T1 * P2)
Since P1 = P2, we can simplify the equation further:
V2 = (V1 * T2) / T1
Substituting the known values into the equation:
V2 = (1.40 L * 450.15 K) / 300.15 K
By performing the calculation, you will find that the new volume (V2) is approximately 2.1 L when the temperature is increased from 27 degrees Celsius to 177 degrees Celsius while keeping the pressure constant.