ABCDEF is a regular hexagon. If BA and CD are extended until they intersect, what is the measure of the angle formed?

hint exterior angle is 360, minus 120

subtract total degrees of triangle

Extend the sides to meet at point E.

Since each exterior angle is 60°,
angle BCE = CBE = 60°

So, now you only have to find the third angle (angle E) of triangle BCE.

Elaborating on 'Steve's answer the third angle should be 60 degrees because the degrees of any triangle add to 180. I think that 'Steve' is suggesting that both B & C are 60 degrees. 60 + 60 = 120. 180 - 120 = 60 so E must be 60 degrees I am 99 percent sure.

I am the Kitty who posted at 8:24 pm earlier. I am not the Kitty who made 204 other posts on this site. I think it's a common name. I will put Kitty (A) after my name from now on OK

To find the measure of the angle formed when BA and CD are extended until they intersect, we need to apply the properties of a regular hexagon.

A regular hexagon has six equal sides and six equal angles. Each angle of a regular hexagon measures 120 degrees.

Now, let's extend BA and CD until they intersect. This means that these two sides will form a straight line, creating a diagonal across the hexagon.

Since a straight line forms a 180-degree angle, the angle formed by extending BA and CD will measure 180 degrees.

Therefore, the measure of the angle formed when BA and CD are extended until they intersect is 180 degrees.