1. The measure of an interior angle of a regular polygon is 20 more than thrice the measure of its adjacent exterior angle. Find the number of sides of the polygon and its total number of diagonals.
2. Find the sum and difference between the sum of the measures of the interior angles of a convex 23-gon and 14-gon.
1. let the number of sides be n
each interior angle = 180(n-2)/n
exterior angle = 360/n
180(n-2)/n = 3(360/n) + 20
180(n-2) = 1080 + 20n
180n - 360 = 1080 + 20n
160n = 1440
n = 9
We have a 9-gon, which is called a enneagon or nonagon
interior angle = 180(7)/9 = 140
exterior angle = 360/9 = 40
is 3 times 40 + 20 = 140 ? , YES
sum interior angles of 23-gon= 180(21) = 3780
sum of interior angles of 14-gon = ....
then take their sum and differenceposted by Reiny