I don't really understand what you mean by "factors"... factors of 2 and factors of 3?
If you have a 1.2M concentration, and you want to dilute it to .45M concentration, you are diluting it by a factor of 1.2/.45 or 2.666666.
To do that, add 1.66666 parts water, one part original solution.
ummm.... i have 1.0 M concentration of CuSO4, and I want to dilute it 0.5 M.
Then the factor is 2as in 1/.5 So for dilution to a factor of 2, one part water, one part original concentration
I apologize for the confusion. When we talk about factors in the context of dilution, we are referring to the ratio between the initial concentration and the final concentration. In your case, you have a 1.0 M concentration of CuSO4 and you want to dilute it to 0.5 M.
To determine the dilution factor, you divide the initial concentration by the final concentration. So, in this case, the dilution factor would be 1.0 M (initial concentration) divided by 0.5 M (final concentration), which equals 2.
To achieve a dilution factor of 2, you would need to add one part of water for every one part of the original concentration. Therefore, for every 1 ml of the 1.0 M CuSO4 solution, you would need to add 1 ml of water. This will result in a final concentration of 0.5 M.
I hope this clarifies the concept of factors in dilution. Let me know if you have any further questions!