solve each system of equation

3x+5y+2z=4
2x-2y+3z=-4
x+y+z=0

*could you show work because I want to learn how you got this answer

double last equation, subtract from second:

-4y+z=-4

triple last equation, subtract from first.

2y -z=4

now add those two equations
-2y= 0
y=0

but -4y+z=-4 so Z=-4

then in the last, x=4

check: first equation
3*4+5*0+2(-4)=4 checks.

Thank you so much