Math

find three consecutive positive odd integers such that the sum of the squares of the first and second integers is equal to the square of the third integer minus 7?

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  1. Let the numbers be x,x+2 and x+4.

    x^2 + (x+2)^2 = (x+4)^2 - 7
    x = 5

    check:

    25+49 = 81-7
    yes

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