I'm having some trouble figuring out how to do the following question:
A ball punted vertically has a hang time of 3.65 seconds. What was its initial velocity? (I use an acceleration of -10 m/s/s)
Thanks!
hf=hi+vi*t-4.9t^2
0=0+vi*t-4.9t^2 solve for vi
Thanks so much!
To solve this question, we can use the kinematic equation that relates the initial velocity (vi), time of flight (t), and acceleration (a) of an object in free fall:
t = (2 * vi) / a
In this case, we are given the time of flight (t) as 3.65 seconds and the acceleration (a) as -10 m/s². We can rearrange the equation to solve for the initial velocity (vi):
vi = (a * t) / 2
Substituting the given values:
vi = (-10 m/s² * 3.65 s) / 2
Now, we can calculate the initial velocity:
vi = -36.5 m/s
Therefore, the initial velocity of the ball when punted vertically was -36.5 m/s.
Note: The negative sign indicates that the initial velocity is in the opposite direction of the acceleration, which makes sense because the ball is being punted upwards against the force of gravity.