What volume of 5.0 M H2SO4 should be diluted to 100mL to prepare a 0.25 M H2SO4 M solution?

I know the molar mass of H2SO4 is 98g but I'm not sure where exactly that fits in and how I'm supposed to get it to be diluted.
Thank you!

The general formula for a dilution is

M₁V₁=M₂V₂

Look familiar? Notice how MV is the number of moles. The number of moles of H₂SO₄ solution do not change.

So, all we have to do now is plug in what we know, and solve for the unknown, which is V₁.

(5.0 M)V₁ = (0.25 M)(100 mL)

V₁ = 5.0 mL

Therefore, 5.0 mL of the 5.0 M solution of H₂SO₄ should be diluted to get 100 mL of a 0.25 M solution of H₂SO₄.

another way.

You want to dilute it 5/.25 or 20 times.
That means 19 parts water, one part stock acid. so you need 1/20 *100ml of stock solution. or 5 ml.

To calculate the volume of a concentrated solution of H2SO4 (5.0 M) that should be diluted to prepare a 0.25 M solution, you can use the formula:

C1V1 = C2V2

Where:
C1 = initial concentration of the concentrated solution (5.0 M)
V1 = initial volume of the concentrated solution
C2 = final concentration of the diluted solution (0.25 M)
V2 = final volume of the diluted solution (100 mL or 0.1 L)

Rearranging the formula to solve for V1:

V1 = (C2 * V2) / C1

Substituting the given values:

V1 = (0.25 M * 0.1 L) / 5.0 M

V1 = 0.005 L or 5 mL

Therefore, you would need to dilute 5 mL of the 5.0 M H2SO4 solution to 100 mL in order to prepare a 0.25 M H2SO4 solution.

To determine the volume of 5.0 M H2SO4 required to prepare a 0.25 M H2SO4 solution, you can use the formula:

M1V1 = M2V2

Where:
M1 = initial molarity of the solution (5.0 M)
V1 = initial volume of the solution to be diluted (unknown)
M2 = final molarity of the solution (0.25 M)
V2 = final volume of the solution (100 mL or 0.1 L)

Rearranging the formula, we get:

V1 = (M2 * V2) / M1

Now, let's substitute the values:

V1 = (0.25 M * 0.1 L) / 5.0 M

Simplifying the equation, we have:

V1 = 0.005 L or 5 mL

Therefore, you would need to take 5 mL of the 5.0 M H2SO4 solution and dilute it to 100 mL to prepare a 0.25 M H2SO4 solution.